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The type names, in turn, are designated to be used in declarations of data members. So, I need 997 bits to store a 3 digit number? The formula for the number of binary bits required to store n integers (for example, 0 to n - 1 ) is: log e (n) / log e (2) and round up. For c++ - Why is signed and unsigned addition converted differently Actually, the range of an unsigned integer is 0 to 2^n - 1 for n bits. However, I've mentioned about 32bit in the [NOTE] part. Step 4: Add all To make it an eight-bit number, add two zeros at the start of the answer. This is preferable to any other behavior. Linear Algebra - Linear transformation question. In that case, I would be assured to be working with only signed (long) integers, right? With you every step of your journey. Therefore, you should split your number into two int64. Web32-bit unsigned integer the possible of use: xmin = 0; ymax = 4294967295; unsigned int x=70000; // x = 70000 unsigned int y = 1025 / 8; // y = 128 y = (unsigned int) (x * y); // z = 875043750 uinteger Description uinteger Used keywords: uinteger Compatible programing languages: Visual Basic .NET | FreeBASIC Examples Visual Basic .NET where \(N_{1} = N/2\) (the integer div operation) and the remainder, \(r_0\text{,}\) is \(0\) or \(1\text{. When you do uint32_t(2)+int32_t(-3), since both operands are the size of an int or larger, no promotion happens and now you are in a case where you have unsigned + signed which results in a conversion of the signed integer into an unsigned integer, and the unsigned value of -1 wraps to being the largest value representable. Then the following rules are applied to the promoted operands: I guess in my current situation (where my unsigned int is 16 bits and the long is 32 bits) one cast is enough. How can I check before my flight that the cloud separation requirements in VFR flight rules are met? Making statements based on opinion; back them up with references or personal experience.